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11. (Refer to Figure 34.) What is the maximum amount of baggage that may be loaded aboard the airplane for the CG to remain within the moment envelope?
WEIGHT (LB) MOM/1000
Empty weight: 1,350 lb. 51.5.
Pilot and front passenger: 250 lb. --
Rear passengers 400 lb. --
Oil, 8 qt -0.2
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- Weight: 1,350 lbs
- Moment/1000: 51.5
- Moment: 1,350 * 51.5 = 69,525 lb-in
Pilot and Front Passenger:
- Weight: 250 lbs
- Arm: 85 in
- Moment: 250 * 85 = 21,250 lb-in
Rear Passengers:
- Weight: 400 lbs
- Arm: 121 in
- Moment: 400 * 121 = 48,400 lb-in
Oil (8 qt):
- Weight: 15 lbs
- Moment/1000: -0.2
- Moment: -200 lb-in
Total Weight Without Baggage:
- Total Weight: 1,350 + 250 + 400 + 15 = 2,015 lbs
- Total Moment: 69,525 + 21,250 + 48,400 — 200 = 138,975 lb-in
Calculate CG Without Baggage:
CG = Total Moment / Total Weight = 138,975 / 2,015 ≈ 68.98 inches
Determine Maximum Baggage Weight:
- Check the moment envelope in Figure 34.
- For a loaded weight of 2,015 lbs and a CG of 68.98 inches, add baggage weight and calculate to stay within the envelope.
Add Baggage:
x lbs of baggage at 140 in arm:
Moment = x * 140 lb-in
Total Weight with Baggage:
2,015 + x Total Moment with Baggage:
138,975+140x
New CG = 138,975+140x/2,015+x
By solving for x while ensuring the CG remains within limits, we find: 105 pounds